C\u00e1ch \u0111\u00e1nh \u0111\u1ec1 theo t\u1ed5ng \u0111\u1ec1 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t t\u00ednh l\u00f4<\/b><\/span><\/h3>\n\u0110\u00e2y l\u00e0 m\u1ed9t trong nh\u1eefng c\u00e1ch ch\u01a1i hi\u1ec7u qu\u1ea3 \u0111\u01b0\u1ee3c nhi\u1ec1u cao th\u1ee7 l\u00f4 \u0111\u1ec1 l\u1ef1a ch\u1ecdn. V\u1edbi c\u00e1ch ch\u01a1i n\u00e0y b\u1ea1n h\u00e3y t\u00ednh nh\u01b0 sau:<\/p>\n
Gi\u1ea3 s\u1eed: Xem \u0111\u1ec1 ng\u00e0y th\u1ee9 nh\u1ea5t ra l\u00e0 AB, \u0111\u1ec1 v\u1ec1 ng\u00e0y th\u1ee9 hai s\u1ebd l\u00e0 DE.<\/p>\n
X\u00e1c \u0111\u1ecbnh m\u1ed1c ng\u00e0y b\u1eaft \u0111\u1ea7u t\u00ednh ta c\u00f3:<\/p>\n
Ta c\u00f3 A + B = C; D + E = F<\/p>\n
Sau \u0111\u00f3 ng\u01b0\u1eddi ch\u01a1i h\u00e3y x\u00e9t c\u00e1c tr\u01b0\u1eddng h\u1ee3p x\u1ea3y ra:<\/p>\n
+ TH 1: N\u1ebfu C < 10, F < 10 l\u1ea5y 10 \u2013 C = Y, 10 \u2013 F = Z. \u0110\u00e1nh YZ cho l\u00f4 ng\u00e0y th\u1ee9 3.<\/p>\n
+ TH 2: N\u1ebfu C > 10, F < 10 l\u1ea5y 20 \u2013 C = Y, 10 \u2013 F = Z, \u0111\u00e1nh l\u00f4 YZ ng\u00e0y th\u1ee9 3.<\/p>\n
+ TH 3: N\u1ebfu C > 10, F > 10 l\u1ea5y 20 \u2013 C = Y, 20 \u2013 F = Z, \u0111\u00e1nh l\u00f4 ng\u00e0y th\u1ee9 3 l\u00e0 YZ.<\/p>\n
+ TH 4: N\u1ebfu C < 10, F > 10. Ta l\u1ea5y hi\u1ec7u 10 \u2013 C = Y, 20 \u2013 F = Z, ng\u00e0y th\u1ee9 3 \u0111\u00e1nh l\u00e0 YZ.<\/p>\n
+ TH 5: C = 0 ho\u1eb7c 10, F = 0 ho\u1eb7c 10 th\u00ec Y, Z \u0111\u1ec1u l\u00e0 0.<\/p>\n
Ng\u01b0\u1eddi ch\u01a1i c\u00f3 th\u1ec3 ch\u01a1i c\u1ea7u n\u00e0y li\u00ean t\u1ee5c trong 3-4 ng\u00e0y. Tuy nhi\u00ean n\u1ebfu sau 4 ng\u00e0y c\u1ea7u kh\u00f4ng ra b\u1ea1n n\u00ean ch\u1ecdn nu\u00f4i l\u00f4 \u0111\u1ec1 kh\u00e1c. C\u00f2n n\u1ebfu nh\u01b0 c\u1ea7u v\u1ec1 l\u1ed9n th\u00ec ngh\u1ec9 3, 4 ng\u00e0y sau c\u1ee9 \u0111\u00e1nh l\u1ea1i, ch\u1eafc c\u00fa c\u00f2n ra.<\/p>\n
Tr\u01b0\u1eddng h\u1ee3p n\u1ebfu nh\u01b0 c\u1ea7u h\u00f4m nay kh\u00f4ng ra, th\u00ec b\u1ea1n n\u00ean ngh\u1ec9 1 ng\u00e0y. Tuy nhi\u00ean xui thay c\u1ea7u n\u00e0y ra \u0111\u00fang h\u00f4m \u0111\u00f3 th\u00ec b\u1ea1n n\u00ean t\u1eeb b\u1ecf c\u1ea7u n\u00e0y v\u00e0 nu\u00f4i c\u00e2u kh\u00e1c. C\u00f2n n\u1ebfu nh\u01b0 c\u1ea7u kh\u00f4ng v\u1ec1 th\u00ec c\u1ee9 \u0111\u00e1nh ti\u1ebfp v\u00ec c\u01a1 h\u1ed9i v\u1eabn c\u00f2n cho b\u1ea1n \u0111\u1ea5y!<\/p>\n
C\u00e1ch \u0111\u00e1nh t\u1ed5ng \u0111\u1ec1 d\u1ef1a v\u00e0o t\u1ed5ng gi\u1ea3i \u0111\u1eb7c bi\u1ec7t<\/b><\/span><\/h3>\nV\u1edbi c\u00e1ch ch\u01a1i n\u00e0y ng\u01b0\u1eddi ch\u01a1i c\u00f3 th\u1ec3 t\u00ednh t\u1ed5ng 5 s\u1ed1 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t. Sau \u0111\u00f3 l\u1ea5y s\u1ed1 \u0111\u00f3 \u0111\u1ec3 l\u00e0m c\u1eb7p l\u00f4 \u0111\u00e1nh cho ng\u00e0y h\u00f4m sau.<\/p>\n
V\u00ed d\u1ee5: Gi\u1ea3i \u0111\u1eb7c bi\u1ec7t h\u00f4m nay ra 51264. Ta t\u00ednh t\u1ed5ng \u0111\u1ec1 gi\u1ea3i n\u00e0y k\u1ebft qu\u1ea3 \u0111\u01b0\u1ee3c con s\u1ed1 16. B\u1ea1n l\u1ea5y con s\u1ed1 n\u00e0y \u0111\u1ec3 \u0111\u00e1nh l\u00f4 \u0111\u1ec1 cho ng\u00e0y h\u00f4m sau. C\u01a1 h\u1ed9i tr\u00fang l\u00e0 kh\u00e1 cao b\u1ea1n nh\u00e9.<\/p>\n
C\u00e1ch \u0111\u00e1nh \u0111\u1ec1 b\u1eb1ng c\u1ed9ng quy lu\u1eadt Pascal<\/b><\/span><\/h3>\n<\/p>\n
C\u00e1ch ch\u01a1i n\u00e0y c\u0169ng r\u1ea5t d\u1ec5, tuy nhi\u00ean hi\u1ec7u qu\u1ea3 mang l\u1ea1i c\u1ef1c cao. Ng\u01b0\u1eddi ch\u01a1i d\u00f9ng 5 s\u1ed1 c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t gh\u00e9p v\u1edbi 5 s\u1ed1 gi\u1ea3i nh\u1ea5t. Ti\u1ebfp theo b\u1ea1n s\u1ebd c\u1ed9ng d\u1ed3n theo quy lu\u1eadt Pascal.<\/p>\n
\n- T\u1ed5ng > 10 th\u00ec ch\u1ec9 l\u1ea5y s\u1ed1 h\u00e0ng \u0111\u01a1n v\u1ecb.<\/li>\n
- C\u1ed9ng \u0111\u1ebfn khi ch\u1ec9 c\u00f2n l\u1ea1i 2 s\u1ed1 th\u00ec l\u1ea5y 2 s\u1ed1 n\u00e0y \u0111\u00e1nh l\u00f4 h\u00f4m sau.<\/li>\n
- V\u1edbi c\u1ea7u n\u00e0y b\u1ea1n n\u00ean nu\u00f4i trong 3 ng\u00e0y.<\/li>\n<\/ul>\n
V\u00ed D\u1ee5:<\/b> G\u0110B ta c\u00f3 l\u00e0 45218, gi\u1ea3i nh\u1ea5t v\u1ec1 10235<\/p>\n
Gh\u00e9p s\u1ed1 l\u1ea1i ta \u0111\u01b0\u1ee3c 4521810235, c\u1ed9ng theo Pascal:<\/p>\n
973991258<\/p>\n
60280373<\/p>\n
6208300<\/p>\n
828130<\/p>\n
00943<\/p>\n
0937<\/p>\n
920<\/p>\n
12<\/p>\n
Ng\u01b0\u1eddi ch\u01a1i s\u1ebd \u0111\u00e1nh con 12 cho ng\u00e0y h\u00f4m sau. \u0110\u00e1nh song th\u1ee7 l\u00f4 th\u00ec \u0111\u00e1nh lu\u00f4n 121 c\u0169ng \u0111\u01b0\u1ee3c n\u1ebfu b\u1ea1n mu\u1ed1n ch\u1eafc \u0103n.<\/p>\n
K\u1ebft lu\u1eadn<\/b><\/span><\/h2>\nTr\u00ean \u0111\u00e2y l\u00e0 3 c\u00e1ch \u0111\u00e1nh \u0111\u1ec1 theo t\u1ed5ng<\/b> hi\u1ec7u qu\u1ea3 nh\u1ea5t 2024 \u0111\u00e3 t\u1ed5ng h\u1ee3p \u0111\u01b0\u1ee3c. Mong r\u1eb1ng nh\u1eefng g\u00ec m\u00e0 ch\u00fang t\u00f4i chia s\u1ebb, s\u1ebd gi\u00fap ng\u01b0\u1eddi ch\u01a1i c\u00f3 nhi\u1ec1u chi\u1ebfn th\u1eafng khi vui ch\u01a1i l\u00f4 \u0111\u1ec1<\/b><\/p>\n